fmod#

Purpose#

Computes the floating-point remainder of \(x/y\).

Format#

r = fmod(x, y)#

Parameters:

x (NxK matrix)
y (LxM matrix) – ExE conformable with x.

Returns:

r (max(N,L) by max(K,M) matrix) – The floating point remainders of \(x/y\).

Examples#

Example 1: Basic usage#

x = { 1.3 2.5,
      4.2 6.0 };

a = fmod(x, 0.5);
b = fmod(x, 2);

After the above code, a and b will equal:

a = 0.3 0  b = 1.3 0.5
    0.2 0      0.2   0

This example extracts all of the years which are evenly divisible by four, from a vector with all of the years between 1900 and 2000.

Example 2: Find years divisible by 4#

/*
** Create a vector with all years from 1900 to 2000
** i.e. 1900, 1901, 1902...2000
*/
yrs = seqa(1900, 1, 101);

// Create a vector with 0 if the element
// is evenly divisible by 4
mask = fmod(yrs, 4);

// Return all rows where 'mask' is equal to 0
// (or delete all rows if they are non-zero)
yrs_4 = delif(yrs, mask);

// Print the first 10 rows
print yrs_4[1:10];

produces:

Remarks#

Returns the floating-point remainder r of \(x/y\) such that \(x = iy + r\), where i is an integer, r has the same sign as x and \(\|r\| < \|y\|\).

Compare this with %, the modulo division operator. (See Operators.)