# delif¶

## Purpose¶

Deletes rows from a matrix. The rows deleted are those for which there is a 1 in the corresponding row of e.

## Format¶

new_x = delif(x, e)
Parameters:
• x (NxK matrix) – data

• e (Nx1 logical vector) – vector of 0’s and 1’s

Returns:

new_x (MxK matrix) – consisting of the rows of x for which there is a 0 in the corresponding row of e. If no rows remain, delif() will return a scalar missing.

## Examples¶

### Basic usage with column vector¶

// Create column vector
x = { 1.5,
0.8,
0.7,
1.2,
1.9,
0.2,
2.0 };

// Create logical vector of 1's and 0's
e = x .> 1;

/*
** Assign 'new_x' to be equal to 'x'
** with the rows removed in which 'e' equals 1
*/
new_x = delif(x, e);


After the code above, new_x should equal:

0.8
0.7
0.2


### Matrix case¶

In this example, we will remove all observations in which the value of the third column is 3.

// Create a matrix with 3 columns
x = { 20    10     2,
33    13     3,
37    12     2,
34    12     3,
35     8     1,
25    15     2,
34     8     2,
37     8     1,
37     3     1,
31     4     1 };

// Create logical vector of 1's and 0's
e = x[., 3] .== 3;

/*
** Assign 'new_x' to be equal to 'x' without
** the rows in which the third column equals 3
*/
new_x = delif(x, e);


After the code above, new_x should be equal to:

20     10      2
37     12      2
35      8      1
25     15      2
34      8      2
37      8      1
37      3      1
31      4      1


### Create new ‘x’ and ‘y’ based on ‘y’¶

In this example, we will remove all observations from x and y in which the value of the third column of y is 2.

// Create 'y' matrix
y = { 1,
1,
0,
2,
0,
1,
1,
0,
0,
2 };

// Create 'x'  matrix
x = { 1.6841  -0.1203,
-1.0433   0.2564,
1.2207  -1.4388,
0.7423   0.2133,
0.7288   1.0434,
0.8115   1.8166,
-0.3230   1.4763,
1.2944   0.7635,
1.3839   0.6648,
-0.6330   0.4845 };

// Create logical vector of 1's and 0's
e = y .== 2;

/*
** Assign 'new_x' to be equal to 'x' without
** the rows in which 'y' equals 2
*/
new_x = delif(x, e);

// Remove all observations in which 'y' equals 2
new_y = delif(y, e);


After the code above, new_y and new_x should equal:

new_y = 1   new_x = 1.6841  -0.1203
1           -1.0433   0.2564
0           1.2207  -1.4388
0           0.7288   1.0434
1           0.8115   1.8166
1           -0.3230   1.4763
0           1.2944   0.7635
0           1.3839   0.6648


### Logical comparison of multiple columns¶

x = { 0 10 20,
30 40 50,
60 70 80 };

// Logical vector, comparing two columns
e =(x[., 1] .gt 0) .and (x[., 3] .lt 100);

new_x = delif(x, e);


After the code above:

new_x = 0 10 20


## Remarks¶

The input e will usually be generated by a logical expression using dot operators. For instance:

/*
** Create a vector 'e' with a 1 for each row in which the
** value in the second column of 'x' is less than 100,
** otherwise a 0
*/
e = x[., 2] .> 100;

new_x = delif(x, e);


Or the equivalent statement:

new_x = delif(x, x[., 2] .> 100);


will delete all rows of x whose second element is greater than 100. The remaining rows of x will be assigned to y.

Functions selif()