# fmod¶

## Purpose¶

Computes the floating-point remainder of $$x/y$$.

## Format¶

r = fmod(x, y)
Parameters
• x (NxK matrix) –

• y (LxM matrix) – ExE conformable with x.

Returns

r (max(N,L) by max(K,M) matrix) – The floating point remainders of $$x/y$$.

## Examples¶

### Example 1: Basic usage¶

x = { 1.3 2.5,
4.2 6.0 };

a = fmod(x, 0.5);
b = fmod(x, 2);


After the above code, a and b will equal:

a = 0.3 0  b = 1.3 0.5
0.2 0      0.2   0


This example extracts all of the years which are evenly divisible by four, from a vector with all of the years between 1900 and 2000.

### Example 2: Find years divisible by 4¶

/*
** Create a vector with all years from 1900 to 2000
** i.e. 1900, 1901, 1902...2000
*/
yrs = seqa(1900, 1, 101);

// Create a vector with 0 if the element
// is evenly divisible by 4

// Return all rows where 'mask' is equal to 0
// (or delete all rows if they are non-zero)

// Print the first 10 rows
print yrs_4[1:10];


produces:

1900
1904
1908
1912
1916
1920
1924
1928
1932
1936


## Remarks¶

Returns the floating-point remainder r of $$x/y$$ such that $$x = iy + r$$, where i is an integer, r has the same sign as x and $$\|r\| < \|y\|$$.

Compare this with %, the modulo division operator. (See Operators.)